y^2+(y/2.75)-7=0

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Solution for y^2+(y/2.75)-7=0 equation:



y^2+(y/2.75)-7=0
We add all the numbers together, and all the variables
y^2+(+y/2.75)-7=0
We get rid of parentheses
y^2+y/2.75-7=0
We multiply all the terms by the denominator
y^2*2.75+y-7*2.75=0
We add all the numbers together, and all the variables
y^2*2.75+y-19.25=0
Wy multiply elements
2.75y^2+y-19.25=0
a = 2.75; b = 1; c = -19.25;
Δ = b2-4ac
Δ = 12-4·2.75·(-19.25)
Δ = 212.75
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{212.75}}{2*2.75}=\frac{-1-\sqrt{212.75}}{5.5} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{212.75}}{2*2.75}=\frac{-1+\sqrt{212.75}}{5.5} $

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